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Q.
The density (in $g\, mL^{−1}$) of a $3.60\, M$ sulphuric acid solution that is $29\%\,H_2SO_4$ (Molar mass $= 98\, g mol^{−1}$) by mass will be
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Solution:
Let the density of solution be $‘d’$
Molarity of solution given $= 3.6$
i.e. 1 litre of solution contains 3.6 moles of $H_2SO_4$
or 1 litre of solution contains $3.6 × 98 \,gms$ of $H_2SO_4$
Since, the solution is 29% by mass.
100 gm solution contains 29 gm $H_2SO_4$
$\frac{100}{d}ml$ solution contains $29\, gm$ of $H_2SO_4$
1000 ml solution contains $3.6 × 98 \,gm$ of $H_2SO_4$
$\therefore 3.6\times9.8=\frac{29\times d}{100}\times1000$
$d=1.22$
Hence, (3) is correct.