Let O is the point at centre and P is the point at circumference. Therefore, angle QOR is double the angle QPR. So, it is sufficient to find the angle QOR.
Now, slope of OQ,m1=4/3,
slope of OR,m2=−3/4
Here, m1m2=−1
Therefore, ∠QOR=π/2
which implies that ∠QPR=π/4