The de Broglie wavelength of a particle having mass m and velocity v is

Question

The de Broglie wavelength of a particle having mass m and velocity v is (A) directly proportional to its mass (B) directly proportional to its energy (C) inversely proportional to its momentum (D) directly proportional to its momentum

Tardigrade Admin · Accepted Answer

: de Broglie wavelength (λ )=(h/p)=(h/momentum)=(h/mv) ∴ λ propto (1/momentum(mv)).

Q. The de Broglie wavelength of a particle having mass m and velocity v is

directly proportional to its mass

directly proportional to its energy

inversely proportional to its momentum

directly proportional to its momentum

: de Broglie wavelength $(λ) = \frac{h}{p} = \frac{h}{m o m e n t u m} = \frac{h}{m v}$ $∴$ $λ \propto \frac{1}{m o m e n t u m ( m v )} .$

Q. The de Broglie wavelength of a particle having mass m and velocity v is

directly proportional to its mass

directly proportional to its energy

inversely proportional to its momentum

directly proportional to its momentum

: de Broglie wavelength (λ)=ph​=momentumh​=mvh​ ∴ λ∝momentum(mv)1​.

: de Broglie wavelength $(λ) = \frac{h}{p} = \frac{h}{m o m e n t u m} = \frac{h}{m v}$ $∴$ $λ \propto \frac{1}{m o m e n t u m ( m v )} .$