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Physics
The de Broglie wavelength of a particle having mass m and velocity v is
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Q. The de Broglie wavelength of a particle having mass m and velocity v is
AMU
AMU 1995
A
directly proportional to its mass
B
directly proportional to its energy
C
inversely proportional to its momentum
D
directly proportional to its momentum
Solution:
: de Broglie wavelength $ (\lambda )=\frac{h}{p}=\frac{h}{momentum}=\frac{h}{mv} $ $ \therefore $ $ \lambda \propto \frac{1}{momentum(mv)}. $