The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is

Question

The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is (A) 0.3 mathringA (B) 3.3 mathringA (C) 6.26 mathringA (D) 10 mathringA

Tardigrade Admin · Accepted Answer

De-Broglie wavelength is given by λ=12.27 / √ E 0, where E 0 is the ground state energy of the hydrogen atom whose value is 13.6 V ∴ λ=12.27 /(√1 3.6)=3.33 mathringA

Q. The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is

0.3 $\overset{˚}{A}$

3.3 $\overset{˚}{A}$

6.26 $\overset{˚}{A}$

10 $\overset{˚}{A}$

De-Broglie wavelength is given by
$λ = 12.27/ E_{0}$ ,
where $E_{0}$ is the ground state energy of the hydrogen atom
whose value is $13.6 V$
$∴ λ = 12.27/ (1 3.6) = 3.33 \overset{˚}{A}$

Q. The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is

0.3 A˚

3.3 A˚

6.26 A˚

10 A˚

De-Broglie wavelength is given by λ=12.27/E​0​, where E0​ is the ground state energy of the hydrogen atom whose value is 13.6V ∴λ=12.27/(1​3.6)=3.33A˚

0.3 $\overset{˚}{A}$

3.3 $\overset{˚}{A}$

6.26 $\overset{˚}{A}$

10 $\overset{˚}{A}$

De-Broglie wavelength is given by
$λ = 12.27/ E_{0}$ ,
where $E_{0}$ is the ground state energy of the hydrogen atom
whose value is $13.6 V$
$∴ λ = 12.27/ (1 3.6) = 3.33 \overset{˚}{A}$