Question

The de-Broglie wavelength associated with electron of hydrogen atom in this ground state is

• A. 0.3 $\mathring{A}$
• B. 3.3 $\mathring{A}$
• C. 6.26 $\mathring{A}$
• D. 10 $\mathring{A}$

Answer 1

Answer: (B)

De-Broglie wavelength is given by
$\lambda=12.27 / \sqrt{ E }_{0}$,
where $E _{0}$ is the ground state energy of the hydrogen atom
whose value is $13.6\, V$
$\therefore \lambda=12.27 /(\sqrt{1} 3.6)=3.33 \,\mathring{A}$