Question

The de-Broglie wave length bf the electron in the second bohr orbit is (given $r_0=0.53A^{\circ })$

• A. 3.33$A^o$
• B. 6.66$A^o$
• C. 9.99$A^o$
• D. 1.06$A^o$

Answer 1

Answer: (B)

$2\pi r=n\lambda$
$\therefore \lambda =\frac{2\pi r}{n}=\frac{2\pi r_o{n}^2}{n}=2\pi r_{o}n$