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  4. The de-Broglie wave length bf the electron in the second bohr orbit is (given r0=0.53A°)

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Q. The de-Broglie wave length bf the electron in the second bohr orbit is (given $r_0=0.53A^\circ)$

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Solution:

$2 \pi r = n \lambda$
$\therefore \, \lambda = \frac{2 \pi r}{n} = \frac{2 \pi r_o n^2}{n} = 2 \pi r_o n$