The d-electronic configuration of [ CoCl 4]2- in tetrahedral crystal field is e m t 2 n Sum of "m" and "number of unpaired electrons" is

Question

The d-electronic configuration of [ CoCl 4]2- in tetrahedral crystal field is e m t 2 n Sum of "m" and "number of unpaired electrons" is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Co 2+: 3 d 7 4 s 0, Cl -: WFL <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/8798cfd13ad5bd1955f542ca63c437dc-.png" /> Configuration e 4 t 2 3: m =4 Number of unpaired electrons =3 So, answer =7

Q. The d-electronic configuration of $[C o C l_{4}]^{2 -}$ in tetrahedral crystal field is $e^{m} t_{2}^{n}$ Sum of " $m$ " and "number of unpaired electrons" is

$C o^{2 +} : 3 d^{7} 4 s^{0}, C l^{-} : W F L$

Configuration $e^{4} t_{2}^{3} : m = 4$
Number of unpaired electrons $= 3$
So, answer $= 7$

Q. The d-electronic configuration of [CoCl4​]2− in tetrahedral crystal field is emt2n​ Sum of "m" and "number of unpaired electrons" is

Co2+:3d74s0,Cl−:WFL Configuration e4t2​3:m=4 Number of unpaired electrons =3 So, answer =7

Q. The d-electronic configuration of $[C o C l_{4}]^{2 -}$ in tetrahedral crystal field is $e^{m} t_{2}^{n}$ Sum of " $m$ " and "number of unpaired electrons" is

$C o^{2 +} : 3 d^{7} 4 s^{0}, C l^{-} : W F L$

Configuration $e^{4} t_{2}^{3} : m = 4$
Number of unpaired electrons $= 3$
So, answer $= 7$