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  4. The d-electronic configuration of [ CoCl 4]2- in tetrahedral crystal field is e m t 2 n Sum of m and number of unpaired electrons is

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Q. The d-electronic configuration of $\left[ CoCl _4\right]^{2-}$ in tetrahedral crystal field is $e ^{ m } t _2 ^n$ Sum of "$m$" and "number of unpaired electrons" is

JEE MainJEE Main 2023The d-and f-Block Elements

Solution:

$ Co ^{2+}: 3 d ^7 4 s ^0, Cl ^{-}: WFL $
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Configuration $e ^4 t _2{ }^3: m =4$
Number of unpaired electrons $=3$
So, answer $=7$