Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The curve, with the property that the projection of the ordinate on the normal is constant and has a length equal to ' a ', is
Q. The curve, with the property that the projection of the ordinate on the normal is constant and has a length equal to '
a
', is
485
129
Differential Equations
Report Error
A
x
+
a
ln
(
y
2
−
a
2
+
y
)
=
c
B
x
+
a
2
−
y
2
=
c
C
(
y
−
a
)
2
=
c
x
D
a
y
=
tan
−
1
(
x
+
c
)
Solution:
Ordinate
=
PM
.
Let
P
≡
(
x
,
y
)
[
T
/
S
]
Projection of ordinate on normal
=
PN
PN
=
PM
cos
θ
=
a
(given)
∴
1
+
t
a
n
2
θ
y
=
a
⇒
y
=
a
1
+
(
y
1
)
2
⇒
d
x
d
y
=
a
y
2
−
a
2
⇒
∫
y
2
−
a
2
a
d
y
=
∫
d
x
⇒
a
ln
∣
∣
y
+
y
2
−
a
2
∣
∣
=
x
+
c