The current-voltage graph for a given metallic wire at two different temperatures T1 and T2 is shown in the figure. The temperatures T1 and T2 are related as

Question

The current-voltage graph for a given metallic wire at two different temperatures T1 and T2 is shown in the figure. The temperatures T1 and T2 are related as (A)  T1>T2  (B)  T1<T2  (C)  T1=T2  (D)  T1>2T2

Tardigrade Admin · Accepted Answer

Slope of the V-i curve at any point is equal to resistance at that point. From the curve slope for T1> slope for T2 RT1<RT2 ⇒ Also at higher temperature resistance will be higher so T2>T1.

Q. The current-voltage graph for a given metallic wire at two different temperatures $T_{1}$ and $T_{2}$ is shown in the figure. The temperatures $T_{1}$ and $T_{2}$ are related as

$T_{1} > T_{2}$

$T_{1} < T_{2}$

$T_{1} = T_{2}$

$T_{1} > 2 T_{2}$

Slope of the V-i curve at any point is equal to resistance at that point. From the curve slope for $T_{1} >$ slope for $T_{2}$ $R_{T_{1}} < R_{T_{2}}$ $\Rightarrow$ Also at higher temperature resistance will be higher so $T_{2} > T_{1} .$

Q. The current-voltage graph for a given metallic wire at two different temperatures T1​ and T2​ is shown in the figure. The temperatures T1​ and T2​ are related as

T1​>T2​

T1​<T2​

T1​=T2​

T1​>2T2​

Slope of the V-i curve at any point is equal to resistance at that point. From the curve slope for T1​> slope for T2​ RT1​​<RT2​​ ⇒ Also at higher temperature resistance will be higher so T2​>T1​.