The current passing through a choke coil of self inductance 5 H is decreasing at the rate of 2 A / s. The e.m.f. developed across the coil is

Question

The current passing through a choke coil of self inductance 5 H is decreasing at the rate of 2 A / s. The e.m.f. developed across the coil is (A) 10 V (B) - 10 V (C) - 2.5 V (D) 2.5 V

Tardigrade Admin · Accepted Answer

L=5 H , (d i/d t)=2 A / s ε=(L d i/d t)=5(2)=10 V

Q. The current passing through a choke coil of self inductance $5 H$ is decreasing at the rate of $2 A / s$ . The e.m.f. developed across the coil is

10 V

- 10 V

- 2.5 V

2.5 V

$L = 5 H, \frac{d i}{d t} = 2 A / s$
$ε = \frac{L d i}{d t} = 5 (2) = 10 V$

Q. The current passing through a choke coil of self inductance 5H is decreasing at the rate of 2A/s. The e.m.f. developed across the coil is