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Physics
The current passing through a choke coil of self inductance 5 H is decreasing at the rate of 2 A / s. The e.m.f. developed across the coil is
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Q. The current passing through a choke coil of self inductance $5 \,H$ is decreasing at the rate of $2 \,A / s$. The e.m.f. developed across the coil is
Electromagnetic Induction
A
10 V
38%
B
- 10 V
32%
C
- 2.5 V
15%
D
2.5 V
15%
Solution:
$L=5 \,H , \frac{d i}{d t}=2 \,A / s$
$\varepsilon=\frac{L d i}{d t}=5(2)=10\, V$