The current in the given circuit is

Question

The current in the given circuit is (A) 4.9 A (B) 6.8 A (C) 8.3 A (D) 2.0 A

Tardigrade Admin · Accepted Answer

In given circuit RB and RC are in series. ∴ RB C=6+6=12 Ω text . Now, RA and RB C are in parallel. Therefore, equivalent resistance of circuit, Re q=(12 × 3/12+3)=(36/15). Using Ohm's law, I=(V/Re q)=(4.8/36 / 15)=2 A.

Q. The current in the given circuit is

4.9 A

6.8 A

8.3 A

2.0 A

In given circuit $R_{B}$ and $R_{C}$ are in series.
$∴ R_{BC} = 6 + 6 = 12Ω .$
Now, $R_{A}$ and $R_{BC}$ are in parallel.
Therefore, equivalent resistance of circuit,
$R_{e q} = \frac{12 \times 3}{12 + 3} = \frac{36}{15}$ .
Using Ohm's law, $I = \frac{V}{R _{e q}} = \frac{4.8}{36/15} = 2 A$ .

Q. The current in the given circuit is

4.9 A

6.8 A

8.3 A

2.0 A

In given circuit RB​ and RC​ are in series. ∴RBC​=6+6=12Ω. Now, RA​ and RBC​ are in parallel. Therefore, equivalent resistance of circuit, Req​=12+312×3​=1536​. Using Ohm's law, I=Req​V​=36/154.8​=2A.

In given circuit $R_{B}$ and $R_{C}$ are in series.
$∴ R_{BC} = 6 + 6 = 12Ω .$
Now, $R_{A}$ and $R_{BC}$ are in parallel.
Therefore, equivalent resistance of circuit,
$R_{e q} = \frac{12 \times 3}{12 + 3} = \frac{36}{15}$ .
Using Ohm's law, $I = \frac{V}{R _{e q}} = \frac{4.8}{36/15} = 2 A$ .