Question

The current in the given circuit is

• A. 4.9 A
• B. 6.8 A
• C. 8.3 A
• D. 2.0 A

Answer 1

Answer: (D)

In given circuit $R_{B}$ and $R_{C}$ are in series.
$\therefore R_{B C}=6+6=12 \Omega \text {. }$
Now, $R_{A}$ and $R_{B C}$ are in parallel.
Therefore, equivalent resistance of circuit,
$R_{e q}=\frac{12 \times 3}{12+3}=\frac{36}{15}$.
Using Ohm's law, $I=\frac{V}{R_{e q}}=\frac{4.8}{36 / 15}=2 A$.