The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of 1:16 at an angle of 6m/s , is

Question

The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of 1:16 at an angle of 6m/s , is (A)  4m/s  (B)  2m/s  (C)  1m/s  (D)  10m/s

Tardigrade Admin · Accepted Answer

c=MB sin θ =(m× 2l)× 2× 10-5 sin 30o =15× 10× 10-2× 2× 10-5× (1/2) =1.5× 10-5Nm

Q. The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of $1 : 16$ at an angle of $6 m / s$ , is

$4 m / s$

$2 m / s$

$1 m / s$

$10 m / s$

$c = MB sin θ$ $= (m \times 2 l) \times 2 \times 10^{- 5} sin 30^{o}$ $= 15 \times 10 \times 10^{- 2} \times 2 \times 10^{- 5} \times \frac{1}{2}$ $= 1.5 \times 10^{- 5} N m$

Q. The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of 1:16 at an angle of 6m/s , is

4m/s

2m/s

1m/s

10m/s