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Physics
The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of 1:16 at an angle of 6m/s , is
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Q. The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of $ 1:16 $ at an angle of $ 6m/s $ , is
BVP Medical
BVP Medical 2012
A
$ 4m/s $
B
$ 2m/s $
C
$ 1m/s $
D
$ 10m/s $
Solution:
$ c=MB\sin \theta $ $ =(m\times 2l)\times 2\times {{10}^{-5}}\sin {{30}^{o}} $ $ =15\times 10\times {{10}^{-2}}\times 2\times {{10}^{-5}}\times \frac{1}{2} $ $ =1.5\times {{10}^{-5}}Nm $