Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The couple acting on a magnet of length 10 cm and pole strength 15 Am, kept in a field of $ 1:16 $ at an angle of $ 6m/s $ , is

BVP MedicalBVP Medical 2012

Solution:

$ c=MB\sin \theta $ $ =(m\times 2l)\times 2\times {{10}^{-5}}\sin {{30}^{o}} $ $ =15\times 10\times {{10}^{-2}}\times 2\times {{10}^{-5}}\times \frac{1}{2} $ $ =1.5\times {{10}^{-5}}Nm $