The correctness of velocity of an electron moving with velocity 50 m s- 1 is 0.005 % . The accuracy with which its position can be measured will be

Question

The correctness of velocity of an electron moving with velocity 50 m s- 1 is 0.005 % . The accuracy with which its position can be measured will be (A) 4634× 10- 3 m (B) 4634× 10- 5 m (C) 4634× 10- 6 m (D) 4634× 10- 8 m

Tardigrade Admin · Accepted Answer

Here, Δ v=(0.005 × 50/100)=0.0025 m s- 1 Δ x=(h/m Δ v) =(1.034 × 10- 34/9.1 × 10- 31 × 0.0025)=4634× 10- 5 m

Q. The correctness of velocity of an electron moving with velocity $50 m s^{- 1}$ is $0.005%$ . The accuracy with which its position can be measured will be

$4634 \times 1 0^{- 3} m$

$4634 \times 1 0^{- 5} m$

$4634 \times 1 0^{- 6} m$

$4634 \times 1 0^{- 8} m$

Here, $Δ v = \frac{0.005 \times 50}{100} = 0.0025 m s^{- 1}$
$Δ x = \frac{h}{m Δ v}$
$= \frac{1.034 \times 1 0 ^{- 34}}{9.1 \times 1 0 ^{- 31} \times 0.0025} = 4634 \times 1 0^{- 5} m$

Q. The correctness of velocity of an electron moving with velocity 50ms−1 is 0.005% . The accuracy with which its position can be measured will be

4634×10−3m

4634×10−5m

4634×10−6m

4634×10−8m