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Q. The correctness of velocity of an electron moving with velocity $50 \, m \, s^{- 1}$ is $0.005\%$ . The accuracy with which its position can be measured will be

NTA AbhyasNTA Abhyas 2020

Solution:

Here, $\Delta v=\frac{0.005 \times 50}{100}=0.0025 \, m \, s^{- 1}$
$\Delta x=\frac{h}{m \Delta v}$
$=\frac{1.034 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 0.0025}=4634\times 10^{- 5 \, }m$