The correct structure of Fe ( CO )5 is

Question

The correct structure of Fe ( CO )5 is (A) trigonal bipyramidal (B) octahedral (C) tetrahedral (D) square pyramidal

Tardigrade Admin · Accepted Answer

In Fe ( CO)5, the Fe atom is in dsp 3 hybridised state. Therefore, the shape of molecule is trigonal bipyramidal. The hybridisation is as 26 Fe =1 s2, 2 s2 2 p6, 3 s2 3 p6 3 d6, 4 s2 4 p0 In Fe ( CO )5 the 'Fe' atom is

Q. The correct structure of $F e (CO)_{5}$ is

trigonal bipyramidal

octahedral

tetrahedral

square pyramidal

In $F e (CO)_{5}$ , the Fe atom is in $d s p^{3}$ hybridised state.
Therefore, the shape of molecule is trigonal bipyramidal.
The hybridisation is as
$_{26} F e = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{6}, 4 s^{2} 4 p^{0}$
In $F e (CO)_{5}$ the $^{'} F e^{'}$ atom is

Q. The correct structure of Fe(CO)5​ is