The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is :

Question

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is : (A) 6, 0, 0, + 1/2 (B) 5, 0, 0, + 1/2 (C) 5, 1,0, + 1/2 (D) 5,1, 1, + 1/2.

Tardigrade Admin · Accepted Answer

Rb (Z = 37) = [Kr]36 5s1 ∴ n = 5 l = 0 (for s-orbital) m = 0 (as m = -l to + l) s = + (1/2)

Q. The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is :

6, 0, 0, + 1/2

5, 0, 0, + 1/2

5, 1,0, + 1/2

5,1, 1, + 1/2.

Rb (Z = 37) = $[Kr]^{36} 5 s^{1}$
$∴$ $n$ = 5
$l$ = 0 (for s-orbital)
$m$ = 0 (as $m = - l$ to + $l$ )
$s = + \frac{1}{2}$

Q. The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is :

6, 0, 0, + 1/2

5, 0, 0, + 1/2

5, 1,0, + 1/2

5,1, 1, + 1/2.

Rb (Z = 37) = [Kr]365s1 ∴ n = 5 l = 0 (for s-orbital) m = 0 (as m=−l to + l) s=+21​

Rb (Z = 37) = $[Kr]^{36} 5 s^{1}$
$∴$ $n$ = 5
$l$ = 0 (for s-orbital)
$m$ = 0 (as $m = - l$ to + $l$ )
$s = + \frac{1}{2}$