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Q. The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is :

Solution:

Rb (Z = 37) = $[Kr]^{36} \, 5s^1$
$\therefore $ $n$ = 5
$l $ = 0 (for s-orbital)
$m $ = 0 (as $m = -l$ to + $l$)
$s = + \frac{1}{2}$