Question

The correct sequence of reactions to be performed to convert benzene into $m$-bromoaniline is

• A. bromination, nitration, reduction
• B. reduction, nitration, bromination
• C. nitration, reduction, bromination
• D. nitration, bromination, reduction

Answer 1

Answer: (D)

Conversion of benzene into $m$ -bromoaniline can be done by successive nitration, bromination and reduction using following reagent

Nitration $\to$ conc. $HN{O}_3\mid$ conc. $H_{2}S{O}_4$

Bromination $\to B{r}_2\mid H_{2}O$

Reduction $\to Sn\mid HCl$

Formation of nitrobenzene in the first step direct incoming electrophile towards meta position on the further step reduction of nitro compound produces m- bromoaniline very easily. Complete sequence of the chemical reaction can be shown as