Q. The correct sequence of reactions to be performed to convert benzene into $m$-bromoaniline is
Solution:
Conversion of benzene into $m$ -bromoaniline can be done by successive nitration, bromination and reduction using following reagent
Nitration $\rightarrow$ conc. $HNO _{3} \mid$ conc. $H _{2} SO _{4}$
Bromination $\rightarrow Br _{2} \mid H _{2} O$
Reduction $\rightarrow Sn \mid HCl$
Formation of nitrobenzene in the first step direct incoming electrophile towards meta position on the further step reduction of nitro compound produces m- bromoaniline very easily. Complete sequence of the chemical reaction can be shown as
