The correct order of the number of unpaired electrons in the ions, Cu 2+, Ni 2+, Fe 3+ and Cr 3+ is

Question

The correct order of the number of unpaired electrons in the ions, Cu 2+, Ni 2+, Fe 3+ and Cr 3+ is (A) Cu 2+> Ni 2+> Cr 3+> Fe 3+ (B) Cr 3+> Fe 3+> Ni 2+> Cu 2+ (C) Fe 3+> Cr 3+> Cu 2+> Ni 2+ (D) Fe 3+> Cr 3+> Ni 2+> Cu 2+

Tardigrade Admin · Accepted Answer

Fe +3 has maximum unpaired electrons.

Q. The correct order of the number of unpaired electrons in the ions, $C u^{2 +}$ , $N i^{2 +}, F e^{3 +}$ and $C r^{3 +}$ is

$C u^{2 +} > N i^{2 +} > C r^{3 +} > F e^{3 +}$

$C r^{3 +} > F e^{3 +} > N i^{2 +} > C u^{2 +}$

$F e^{3 +} > C r^{3 +} > C u^{2 +} > N i^{2 +}$

$F e^{3 +} > C r^{3 +} > N i^{2 +} > C u^{2 +}$

$F e^{+ 3}$ has maximum unpaired electrons.

Q. The correct order of the number of unpaired electrons in the ions, Cu2+, Ni2+,Fe3+ and Cr3+ is

Cu2+>Ni2+>Cr3+>Fe3+

Cr3+>Fe3+>Ni2+>Cu2+

Fe3+>Cr3+>Cu2+>Ni2+

Fe3+>Cr3+>Ni2+>Cu2+