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Chemistry
The correct order of the number of unpaired electrons in the ions, Cu 2+, Ni 2+, Fe 3+ and Cr 3+ is
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Q. The correct order of the number of unpaired electrons in the ions, $Cu ^{2+}$, $Ni ^{2+}, Fe ^{3+}$ and $Cr ^{3+}$ is
A
$Cu ^{2+}> Ni ^{2+}> Cr ^{3+}> Fe ^{3+}$
15%
B
$Cr ^{3+}> Fe ^{3+}> Ni ^{2+}> Cu ^{2+}$
15%
C
$Fe ^{3+}> Cr ^{3+}> Cu ^{2+}> Ni ^{2+}$
5%
D
$Fe ^{3+}> Cr ^{3+}> Ni ^{2+}> Cu ^{2+}$
65%
Solution:
$Fe ^{+3}$ has maximum unpaired electrons.