The correct order of increasing solubility of AgCl in (A) water (B) 0.1 M NaCl (C) 0.1 BaCl 2( D ) 0.1 M NH 3 is

Question

The correct order of increasing solubility of AgCl in (A) water (B) 0.1 M NaCl (C) 0.1 BaCl 2( D ) 0.1 M NH 3 is (A) D > A > B > C (B) D > C > B > A (C) B > A > D > C (D) A > D > B > C

Tardigrade Admin · Accepted Answer

The solubility decreases by common ion effect

A =

in water solubility of

A g Cl

is very less

B [C l^{-}] = 0.1

C [C l^{-}] = 0.2

D =

Soluble complex compound is formed

∵ [A g (N H_{3})_{2}] Cl

∴

Solubility of

A g Cl

is

D > A > B > C

Q. The correct order of increasing solubility of AgCl in (A) water (B) 0.1MNaCl (C) 0.1BaCl2​(D)0.1MNH3​ is

D > A > B > C

D > C > B > A

B > A > D > C

A > D > B > C

The solubility decreases by common ion effect A= in water solubility of AgCl is very less B[Cl−]=0.1 C[Cl−]=0.2 D= Soluble complex compound is formed ∵[Ag(NH3​)2​]Cl ∴ Solubility of AgCl is D>A>B>C

Q. The correct order of increasing solubility of $A g Cl$ in (A) water (B) $0.1 M N a Cl$ (C) $0.1 B a C l_{2} (D) 0.1 MN H_{3}$ is

The solubility decreases by common ion effect

$A =$ in water solubility of $A g Cl$ is very less

$B [C l^{-}] = 0.1$

$C [C l^{-}] = 0.2$

$D =$ Soluble complex compound is formed

$∵ [A g (N H_{3})_{2}] Cl$

$∴$ Solubility of $A g Cl$ is $D > A > B > C$