1. Tardigrade
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  3. Chemistry
  4. The correct order of increasing solubility of AgCl in (A) water (B) 0.1 M NaCl (C) 0.1 BaCl 2( D ) 0.1 M NH 3 is

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Q. The correct order of increasing solubility of $AgCl$ in (A) water (B) $0.1 \,M\, NaCl$ (C) $0.1 BaCl _{2}( D ) 0.1 M NH _{3}$ is

Equilibrium

Solution:

The solubility decreases by common ion effect

$A =$ in water solubility of $AgCl$ is very less

$B \left[ Cl ^{-}\right]=0.1$

$C \left[ Cl ^{-}\right]=0.2$

$D =$ Soluble complex compound is formed

$\because \left[ Ag \left( NH _{3}\right)_{2}\right] Cl$

$\therefore $ Solubility of $AgCl$ is $D > A > B > C$