The correct order of increasing radii of the ions Br -, F -, O 2- and S 2- is as follows:

Question

The correct order of increasing radii of the ions Br -, F -, O 2- and S 2- is as follows: (A) Br -< F -< O 2-< S 2- (B) S 2-< O 2-< F -< Br - (C) F -< O 2-< S 2-< Br - (D) F -< Br -< O 2-< S 2-

Tardigrade Admin · Accepted Answer

F -and O 2- are isoelectronic but nuclear charge of F -> O 2-. Hence, ionic radius of F -< O 2-

Q. The correct order of increasing radii of the ions $B r^{-}, F^{-}, O^{2 -}$ and $S^{2 -}$ is as follows:

$B r^{-} < F^{-} < O^{2 -} < S^{2 -}$

$S^{2 -} < O^{2 -} < F^{-} < B r^{-}$

$F^{-} < O^{2 -} < S^{2 -} < B r^{-}$

$F^{-} < B r^{-} < O^{2 -} < S^{2 -}$

$F^{-}$ and $O^{2 -}$ are isoelectronic but nuclear charge of $F^{-} > O^{2 -}$ . Hence, ionic radius of $F^{-} < O^{2 -}$

Q. The correct order of increasing radii of the ions Br−,F−,O2− and S2− is as follows:

Br−<F−<O2−<S2−

S2−<O2−<F−<Br−

F−<O2−<S2−<Br−

F−<Br−<O2−<S2−