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Q. The correct order of increasing radii of the ions $Br ^{-}, F ^{-}, O ^{2-}$ and $S ^{2-}$ is as follows:

The Solid State

Solution:

$F ^{-}$and $O ^{2-}$ are isoelectronic but nuclear charge of $F ^{-}> O ^{2-}$. Hence, ionic radius of $F ^{-}< O ^{2-}$