Q.
The correct order of electrical conductivity of the given complexes is
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J & K CETJ & K CET 2017Coordination Compounds
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Solution:
Electrical conductivity of the complexes is directly proportional to the number of ions (n) produced
The dissociation of given complexes can be shown as, [Ni(NH3)4Cl2]→ No ions [CO(NH3)4Cl2]Cl→[Co(NH3)4Cl2]++Cl−;(n=2) K2[PtCl6]→2K++[ptCl6]2−;(n=3) K4[Fe(CN)6]→4K++[Fe(CN)6]4−;(n=5)
Thus, the increasing order of electrical conductivity is: [Ni(NH3)4Cl2]<[Co(NH3)4Cl2]Cl<K2[PtCl6]<K4[Fe(CN)6]