Thank you for reporting, we will resolve it shortly
Q.
The correct order of electrical conductivity of the given complexes is
J & K CETJ & K CET 2017Coordination Compounds
Solution:
Electrical conductivity of the complexes is directly proportional to the number of ions (n) produced
The dissociation of given complexes can be shown as,
$[Ni(NH_{3})_{4} Cl_{2}] \to $ No ions
$[CO(NH_{3})_{4}Cl_{2}]Cl \to [Co(NH_{3})_{4}Cl_{2}]^{+}+Cl^{-}; (n=2)$
$K_{2}[PtCl_{6}] \to 2K^{+}+[ptCl_{6}]^{2-} ; (n=3)$
$K_{4}[Fe(CN)_{6}] \to 4K^{+}+[Fe(CN)_{6}]^{4-}; (n=5)$
Thus, the increasing order of electrical conductivity is:
$[Ni(NH_{3})_{4}Cl_{2}] <\, [Co(NH_{3})_{4}Cl_{2}]Cl <\, K_{2}[PtCl_{6}]<\, K_{4}[Fe(CN)_{6}]$