Question

The correct order of basic ties of $PhN{H}_2,P{h}_{2}NH$ and Cyclohexyl- $N{H}_2(C)$ is

• A. A > B > C
• B. A > C > B
• C. C > A > B
• D. C > B > A

Answer 1

Answer: (C)

$C>A>B$
In diphenylamine, there are two electron withdrawing phenyl groups with $-I$ effect while there is one such group in aniline. Therefore, diphenylamine is a weaker base than aniline which, in turn, is less basic than cyclohexyl amine in which the electron pair on nitrogen can be easily donated to a Lewis acid.