Q. The correct order of basic ties of $PhNH_2, P h_{2} NH$ and Cyclohexyl- $NH _{2}( C )$ is
AMUAMU 2012
Solution:
$ C > A > B$
In diphenylamine, there are two electron withdrawing phenyl groups with $-I$ effect while there is one such group in aniline. Therefore, diphenylamine is a weaker base than aniline which, in turn, is less basic than cyclohexyl amine in which the electron pair on nitrogen can be easily donated to a Lewis acid.
