Question

The correct increasing bond angle among $B{F}_3,P{F}_3$ and $Cl{F}_3$ follows the order

• A. $B{F}_3<P{F}_3<CI{F}_3$
• B. $P{F}_3<B{F}_3<CI{F}_3$
• C. $CI{F}_3<P{F}_3<B{F}_3$
• D. $B{F}_3<P{F}_3>CI{F}_3$

Answer 1

Answer: (C)

$B{F}_3$ It has $s{p}^2$ hybridization and bond angle is $120^{\circ }P{F}_{3}It$ has $s{p}^3$ hybridization and bond angle is less than $109^{\circ }28$ ' but greater than $100^{+}$due to lone pair bond pair repulsions. $CI{F}_3$ has $s{p}^{3}d$ hybridization and bond angle is $90^{\circ }$