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Q. The correct increasing bond angle among $BF _{3}, PF _{3}$ and $ClF _{3}$ follows the order

Classification of Elements and Periodicity in Properties

Solution:

$BF _{3}$ It has $sp ^{2}$ hybridization and bond angle is $120^{\circ} PF _{3} It$ has $sp ^{3}$ hybridization and bond angle is less than $109^{\circ} 28$ ' but greater than $100^{+}$due to lone pair bond pair repulsions. $CIF _{3}$ has $sp ^{3} d$ hybridization and bond angle is $90^{\circ}$