Question

The correct graph between the maximum energy of a photoelectron and the inverse of wavelength of the incident radiation is given by the curve

• A. A
• B. B
• C. C
• D. None of the above

Answer 1

Answer: (A)

$K_{\max }=hv-h{v}_0=\frac{hc}{\lambda }-\frac{hc}{{\lambda }_0}$
i.e., graph between $K_{\max }$and $\frac{1}{\lambda }$ will be straight line having slope $(hc)$ and intercept $\frac{hc}{{\lambda }_0}$ on $KE$ axis.