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  4. The correct graph between the maximum energy of a photoelectron and the inverse of wavelength of the incident radiation is given by the curve

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Q. The correct graph between the maximum energy of a photoelectron and the inverse of wavelength of the incident radiation is given by the curvePhysics Question Image

Dual Nature of Radiation and Matter

Solution:

$K_{\max }=h v-h v_{0}=\frac{h c} {\lambda}-\frac{h c}{\lambda_{0}}$
i.e., graph between $K_{\max }$and $\frac{1}{\lambda}$ will be straight line having slope $(h c)$ and intercept $\frac{h c}{\lambda_{0}}$ on $K E$ axis.