Question

The correct curve between the stopping potential ($V_s$ ) and intensity $(I)$ of incident light is

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

We have, n $=\frac{P}{hv}=\frac{10\times 10^3}{6.6\times 10^{-34}\times 880\times 10^3}$ = $1.72\times 10^{31}$