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  4. The correct curve between the stopping potential ( Vs ) and intensity (I) of incident light is

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Q. The correct curve between the stopping potential ($ V_s$ ) and intensity $(I)$ of incident light is

Haryana PMTHaryana PMT 2005Dual Nature of Radiation and Matter

Solution:

We have, n $ = \frac{ P }{ hv } = \frac{ 10 \times 10^3 }{ 6.6 \times 10^{ - 34 } \times 880 \times 10^3 } $ = $ 1.72 \times 10^{ 31 } $