The correct bond order of S-O bond in decreasing order is

Question

The correct bond order of S-O bond in decreasing order is (A) OSF 2> OSCl 2> OSBr 2 (B) OSCl 2> OSBr 2> OSF 2 (C) OSF 2> OSBr 2> OSCl 2 (D) OSBr 2> OSCl 2> OSF 2

Tardigrade Admin · Accepted Answer

As electronegativity of halogen attached with sulphur increases, sulphur becomes more electron deficient and hence its tendency to get electrons from oxygen through p π-d π bonding also increases, i.e., extent of p π-d π bonding increases and hence bond order also increases.

Q. The correct bond order of $S - O$ bond in decreasing order is

$OS F_{2} > OSC l_{2} > OSB r_{2}$

$OSC l_{2} > OSB r_{2} > OS F_{2}$

$OS F_{2} > OSB r_{2} > OSC l_{2}$

$OSB r_{2} > OSC l_{2} > OS F_{2}$

As electronegativity of halogen attached with sulphur increases, sulphur becomes more electron deficient and hence its tendency to get electrons from oxygen through $p π - d π$ bonding also increases, i.e., extent of $p π - d π$ bonding increases and hence bond order also increases.

Q. The correct bond order of S−O bond in decreasing order is

OSF2​>OSCl2​>OSBr2​

OSCl2​>OSBr2​>OSF2​

OSF2​>OSBr2​>OSCl2​

OSBr2​>OSCl2​>OSF2​