Question

The correct bond order of $S-O$ bond in decreasing order is

• A. $OSF _{2}> OSCl _{2}> OSBr _{2}$
• B. $OSCl _{2}> OSBr _{2}> OSF _{2}$
• C. $OSF _{2}> OSBr _{2}> OSCl _{2}$
• D. $OSBr _{2}> OSCl _{2}> OSF _{2}$

Answer 1

Answer: (A)

As electronegativity of halogen attached with sulphur increases, sulphur becomes more electron deficient and hence its tendency to get electrons from oxygen through $p \pi-d \pi$ bonding also increases, i.e., extent of $p \pi-d \pi$ bonding increases and hence bond order also increases.