Question

The coordination number of $S{r}^{2+}$ ion in $Sr{F}_2$, if ionic radii are r $(S{i}^{2+})$ = 113 pm and r $(F^{-})$ = 136 pm; is

• A. 6
• B. 8
• C. 12
• D. 4

Answer 1

Answer: (B)

Radius ratio $=\frac{r^{+}}{r^{-}}=\frac{113}{136}$
$=0.830>0.732$.
The coordination number of $S{r}^{2+}$ is $8$.