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Q. The coordination number of $Sr^{2+}$ ion in $SrF_2$, if ionic radii are r $(Si^{2+})$ = 113 pm and r $(F^-)$ = 136 pm; is

The Solid State

Solution:

Radius ratio $ = \frac{r^+}{r^-} = \frac{113}{136}$
$ = 0.830 > 0.732$.
The coordination number of $Sr^{2+}$ is $8$.