The co-ordination number and the oxidation state of the element 'M' in the complex [ M(en)2(C2O4)]NO2 where (en) is ethane-1,2-diamine) are, respectively

Question

The co-ordination number and the oxidation state of the element 'M' in the complex [ M(en)2(C2O4)]NO2 where (en) is ethane-1,2-diamine) are, respectively (A) 6 and 3 (B) 6 and 2 (C) 4 and 2 (D) 4 and 3

Tardigrade Admin · Accepted Answer

For the given coordinate compound. [M (en)2 (C2O4)]NO2 (i) ∵ All the (3) ligands are bi dented thus its coordinate number =6 (ii) Oxidation number of M will be x+0+2 ×(-2)=0-1 ∴ x (oxidation number of M)=+ 3

Q. The co-ordination number and the oxidation state of the element $^{'} M^{'}$ in the complex $[M (e n)_{2} (C_{2} O_{4})] N O_{2}$ ${$ where (en) is ethane-1,2-diamine) are, respectively

$6$ and $3$

$6$ and $2$

$4$ and $2$

$4$ and $3$

For the given coordinate compound.

$[M (e n)_{2} (C_{2} O_{4})] N O_{2}$

(i) $∵$ All the (3) ligands are bi dented thus its coordinate number $= 6$

(ii) Oxidation number of $M$ will be

$x + 0 + 2 \times (- 2) = 0 - 1$

$∴ x$ (oxidation number of $M) = + 3$

Q. The co-ordination number and the oxidation state of the element ′M′ in the complex [M(en)2​(C2​O4​)]NO2​ { where (en) is ethane-1,2-diamine) are, respectively

6 and 3

6 and 2

4 and 2

4 and 3