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Chemistry
The co-ordination number and the oxidation state of the element 'M' in the complex [ M(en)2(C2O4)]NO2 where (en) is ethane-1,2-diamine) are, respectively
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Q. The co-ordination number and the oxidation state of the element $'M'$ in the complex $[ M(en)_{2}(C_{2}O_{4})]NO_{2}$ $\{$ where (en) is ethane-1,2-diamine) are, respectively
KCET
KCET 2017
Coordination Compounds
A
$6$ and $3$
40%
B
$6$ and $2$
30%
C
$4$ and $2$
20%
D
$4$ and $3$
10%
Solution:
For the given coordinate compound.
$[M (en)_2 (C_2O_4)]NO_2$
(i) $\because$ All the (3) ligands are bi dented thus its coordinate number $=6$
(ii) Oxidation number of $M$ will be
$x+0+2 \times(-2)=0-1$
$\therefore \,x$ (oxidation number of $M)=+ 3$