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Tardigrade
Question
Chemistry
The coordination number and oxidation number of X in the compound [X(SO4)(NH3)5]Cl will be
Q. The coordination number and oxidation number of X in the compound
[
X
(
S
O
4
)
(
N
H
3
)
5
]
Cl
will be
1485
216
Coordination Compounds
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A
6 and +3
51%
B
2 and -6
20%
C
10 and -3
14%
D
6 and +4
14%
Solution:
In
[
X
(
S
O
4
)
(
N
H
3
)
5
]
Cl
, coordination number of X is
6
(
S
O
4
2
−
is binegative ligand and
N
H
3
is neutral ligand).
Let oxidation state of X be a.
Then, in
[
X
(
S
O
4
)
(
N
H
3
)
5
]
+
a
−
2
=
+
1
⇒
a
=
+
3