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  4. The coordination number and oxidation number of X in the compound [X(SO4)(NH3)5]Cl will be

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Q. The coordination number and oxidation number of X in the compound $[X(SO_4)(NH_3)_5]Cl$ will be

Coordination Compounds

Solution:

In $[X(SO_4)(NH_3)_5]Cl$, coordination number of X is $6\, (SO_4^{ 2-}$ is binegative ligand and $NH_3$ is neutral ligand).
Let oxidation state of X be a.
Then, in $[X(SO_4)(NH_3)_5]^+$
$a - 2 = +1 \quad⇒\quad a = + 3$