Question

The concentration (in mol/L) of the solution having osmotic pressure $0.0821$ atm at $300K$ will be

• A. 0.33
• B. 0.066
• C. $0.3\times 10^{-2}$
• D. 3

Answer 1

Answer: (C)

$\pi =CRT$
$C=\frac{\pi }{RT}=\frac{0.0821}{0.0821\times 300}$
$=0.33\times 10^{-2}mol/L$